## Post: Modified Date

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\)

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\)

Test krm